Question

What was the acceleration of a runner that ran a distance of 200 meters in 17 seconds?

Answer 1

Given:

The distance is,

`s=200\text{ m}`

The time is,

`t=17\text{ s}`

To find:

The acceleration

Step-by-step explanation:

We know when an object moves with an initial speed of zero, the distance is,

`s=(1)/(2)at^2`

Here, 'a' is the acceleration of the object.

Substituting the values we get,

`\begin{gathered} 200=(1)/(2)* a*17^2 \\ a=(200*2)/(17^2) \\ a=(400)/(289) \\ a=1.38\text{ m/s}^2 \end{gathered}`

Hence, the acceleration is,

`a=1.38\text{ m/s}^2`