Question

Suppose c and d vary inversely, and d = 2 when c = 17

Answer 1

Step 1:

In this question, we are given the following:

Step 2:

The details of the solution are as follows:

`\begin{gathered} Since\text{ c and d are inversely proportional to each other.} \\ This\text{ means that:} \\ c\text{ }\propto\text{ }(1)/(d) \\ \text{c =}(k)/(d)\text{ , where k is a constant} \\ Now\text{ d= 2 and c = 17 , we have that:} \end{gathered}`
`\begin{gathered} 17\text{= }(k)/(2) \\ This\text{ implies that:} \\ \text{k = 17 x 2 = 34} \end{gathered}`

PART ONE:

The equation that models the variation is:

`\text{c =}(34)/(d)`

PART TWO:

The value of d when c = 68;

`\begin{gathered} 68\text{ =}(34)/(d) \\ Making\text{ d the subject of the formulae, we have that:} \\ \text{d =}(34)/(68)=\text{ }(1)/(2) \\ Hence,\text{ d = }(1)/(2) \end{gathered}`