Given:
a.) The new height is 100.05% of what it was the previous year.
b.) The average male's height was 54 inches in 1548.
For us to be able to determine the average height of a male in 2008, we will be using the geometric sequence formula:
![A_n\text{ = }A_1(r)^(n-1)](https://img.qammunity.org/2023/formulas/mathematics/college/womhnh6ic6160imz3hxdjhe4q6ydxx2fpr.png)
Where,
An = The average height of a male in 2008
A1 = 54 inches
r = 100.05% = 100.05/100 = 1.0005
n = (2008 - 1548) + 1 = 460 + 1 = 461
We get,
![A_n\text{ = }A_1(r)^(n-1)](https://img.qammunity.org/2023/formulas/mathematics/college/womhnh6ic6160imz3hxdjhe4q6ydxx2fpr.png)
![A_n\text{ = }(54)(1.0005)^(461-1)\text{ = }(54)(1.0005)^(460)](https://img.qammunity.org/2023/formulas/mathematics/college/lfzc6on7jwkfebmwff389j29b7mnoz2j5d.png)
![=(54)(1.2585276666222281763001496826748)](https://img.qammunity.org/2023/formulas/mathematics/college/yhz6s0p1igc02awi2fk68z9jimeklkhvew.png)
![=\text{ }67.960493997600321520208082864439](https://img.qammunity.org/2023/formulas/mathematics/college/u24ez94869ze19urp6cbllsxkdfmf2ia5k.png)
![\text{ }\approx\text{ 67. 96 inches}](https://img.qammunity.org/2023/formulas/mathematics/college/pnifoq9tvlk9cng5gwai74t2leee60m94o.png)
Therefore, in 2008, the average height of a male will be 67.96 inches.