Question

Find the equation of the line passing through the given pair of points. Write the equation in slope-intercept form.(2,6) and (-5,6)

Answer 1

To answer this question we will use the following two-points formula for the equation of a line that passes through two given points:

`y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)\text{.}`

Therefore, the equation of the line that passes through (2,6) and (-5,6) is:

`y-6=(6-6)/(-5-2)(x-2)\text{.}`

Simplifying the above equation we get:

`\begin{gathered} y-6=(0)/(-7)(x-2), \\ y-6=0. \end{gathered}`

Adding 6 to the above equation we get:

`\begin{gathered} y-6+6=0+6, \\ y=6. \end{gathered}`

Answer:

`y=6.`