SOLUTION:
Step 1:
In this question, we are given the following:
A toy boat is seen floating down a river.
The toy boat is first spotted 60 feet away.
A few moments later the toy boat is 45 feet away, making a 55° angle between the two sightings.
How far did the toy boat travel? Round to the nearest tenth.
Step 2:
The details of the solution are as follows:
The details of the diagram are as follows
Using cosine rule

Here

![\begin{gathered} c^2=60^2+45^2-2(60)(45)\cos (55^0) \\ \\ \Rightarrow c=\sqrt[]{60^2+45^2-2(60)(45)\cos(55^0)}=\sqrt[]{2527.687244}\approx50.3(\text{ to the nearest tenth}) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/9dcrm9qi81u0689fyupmakc6cs5ayzzybj.png)
Conclusion
Therefore, the toy boat traveled a distance of 50.3 feet (