Question

Find the probability of Taylor rolling a 1 on the number cube then filling a 3 on her second roll. Independent or Dependent

Answer 1

Probability of Taylor rolling a 1 on the first roll and a 3 on the second roll

= (1/36)

Step-by-step explanation

Probability of an event is calculated as the number of elements in the event divided by the total number of elements in the sample space.

For this question, the two probabilities are independent of each other, that is, the chances of getting a 1 does not depend on the chances of getting a 3 on the second roll.

P(1)

Number of elements that are 1 = 1

Total number of elements on a number cube = 6

P(1) = (1/6)

P(3)

Number of elements that are 3 = 1

Total number of elements on a number cube = 6

P(3) = (1/6)

So,

Probability of Taylor rolling a 1 on the first roll and a 3 on the second roll

= (1/6) × (1/6)

= (1/36)

Hope this Helps!!!