Question

Which is the following exponentail functions has an initial value of 5

Answer 1

Given exponential functions :

To find which function has initial value of 5, substitute with x = 0 at each function

a)

`\begin{gathered} y=67\cdot((2)/(3))^x \\ \\ x=0\rightarrow y=67\cdot((2)/(3))^0=67\cdot1=67 \end{gathered}`

b)

`\begin{gathered} y=1.3(6)^x \\ x=0\rightarrow y=1.3\cdot1=1.3 \end{gathered}`

C)

`\begin{gathered} y=5(0.8)^x \\ \\ x=0\rightarrow y=5(0.8)^0=5\cdot1=5 \end{gathered}`

d)

`\begin{gathered} y=0.2(5)^x \\ \\ x=0\rightarrow y=0.2\cdot1=0.2 \end{gathered}`

So, the answer is option c