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Question ♀️♀️♀️♀️♀️♀️♀️A rock is thrown from a cliff into a ravine. The function h(t) = -14t^2 + 182t + 3260 describes the height, in feet, of the rock t second after it is thrown. What is the height of the rock, in feet, 10 seconds after it is thrown?

1 Answer

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h(t) = -14t^2 + 182t + 3260

Where:

t = seconds

Replace t= 10 and solve

h(10) = -14(10)^2 + 182(10) + 3260

h(10) = -14(100) +1820 +3260

h(10)= -1400+1820+3260

h(10)= 3680

Height of the rock after 10 seconds = 3680 ft

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