For a general quadratic polynomial of the form:

the solution is
![x_(1,2)=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://img.qammunity.org/2023/formulas/mathematics/college/li72dimqx1poek8bdg3bs589861h83kfxl.png)
this formula is called "the quadratic formula". There are 2 solutions indicated by the subindex 1 and 2 in x.
In our case, by comparing polynomials, we can see that

becuase our polynomial is

in which we moved 1 to the left hand side as -1.
Then, by applying the quadratic formula, we have
![x_(1,2)=\frac{-(-1)\pm\sqrt[]{(-1)^2-4(2)(-6)}}{2(2)}](https://img.qammunity.org/2023/formulas/mathematics/college/pt29t4dmayued6jtkljqiiwanxxa9x6y6l.png)
Then ,the first solution is
![x_1=\frac{-(-1)+\sqrt[]{(-1)^2-4(2)(-6)}}{2(2)}](https://img.qammunity.org/2023/formulas/mathematics/college/aagqqz9v6n0tpwhzk8shv0k0lf9tb4qpcv.png)
and the