The volume of cone =

where r = 15cm
h = 10 cm
PI = 3.14
V= 1/3 x 3.14 x 15 x 15 x 10
V = 2355/3

Also, let us consider the volume of the rectangular solid
The volume of the rectangular solid = L X B X H
L= 14cm, B = 17cm , H = 25cm
V = 14 x 17 x 25

To determine the number of full cones of water that will be obtained in the rectangular solid, we will divide the volume of the rectangular solid by that of the cone

Since the water shouldn't overflow, we will round up to the nearest whole number
=> 8