1 Answer

Tanvi B · Answer 1 · 2023-08-25T13:05:40+0000

Solution

- To solve the question, we should bring the integrals with the same lower bound together.

- Thus, we have:

$\begin{gathered} \int_(-2)^2f(x)+\int_2^5f(x)-\int_(-2)^(-1)f(x) \\ \\ \int_(-2)^2f(x)-\int_(-2)^(-1)f(x)+\int_2^5f(x) \\ \\ \int_(-1)^2f(x)+\int_2^5f(x) \\ \\ =\int_(-1)^5f(x) \end{gathered}$

Final Answer

The answer

$\begin{gathered} a=-1 \\ b=5 \end{gathered}$

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