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Solving a distance right time problem using a system of linear equations

Solving a distance right time problem using a system of linear equations-example-1
User Timonvlad
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Solution:


\begin{gathered} Speed\text{ }train1\text{ }=x \\ Speed\text{ }train2=x+13 \end{gathered}

In 2 hours;

Train 1 would have covered 2x miles

Train 2 would have covered 2x+26 miles.

Thus;


\begin{gathered} 2x+2x+26=350 \\ 4x=324 \\ x=(81mi)/(h) \end{gathered}

Thus the speeds of the trains are 94 mi/h and 81 mi/h

User Susannah Potts
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