The perimeter of a rectangle is 130 ft.
Let x be the length of the rectangle and y be the width of the rectangle.
Then,
![\begin{gathered} 2(x+y)=130 \\ x+y=65\ldots\ldots(1) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/yohc1i5x1kqp2jak1pb5jw9b3itishb0h3.png)
Lenght is 9 feet shorter than width. Therefore,
![x=y-9\ldots\ldots(2)](https://img.qammunity.org/2023/formulas/mathematics/college/qgguab2pqwhjog2embm004k6t16pr1owpv.png)
Put equation (2) in (1) implies,
![\begin{gathered} y-9+y=65 \\ 2y=74 \\ y=37 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/p9adtjxf9j6b4jv4oyjexh0y9ie19crj52.png)
Then, the value of x is ,
![\begin{gathered} x=37-9 \\ x=28 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/7gfnjayy3qngzzqrijsznp6iomzcv3t3f8.png)
Therefore, the dimensions are 28 and 37.