Question

a gun with a muzzle velocity of 100m/s is fired horizontally from a tower neglecting air resistance how far downrange will the bullet be 1 s later

Answer 1

While the bullet is in the air, there are no horizontal forces acting on it (we're neglecting air resistance and there is gravity, but that is a vertical that no affect x-movement). Therefore, the acceleration of the bullet in the x-direction can be solved as a rectilinear motion problem.

we have the next information

v=100 m/s

t=1 s

We will use the next formula

`v=(d)/(t)`

where v is the velocity, d is the distance and t is the time

we substitute the values given

`100=(d)/(1)`

then we isolate the d

`d=100\cdot1=100m`

After 1 second, the bullet will be 100 m away.