Question

write the slope intercerp form of the queation of the line trought the given pointsi know the explication

Answer 1

To find the equation of the line that passes through the points (2, 4) and (0, 1), we have to find the slope of the line using the rule

`m=(y_2-y_1)/(x_2-x_1)`

Let x1 = 2 and y1 = 4

Let x2 = 0 and y2 = 1

`\begin{gathered} m=(1-4)/(0-2) \\ m=(-3)/(-2) \\ m=(3)/(2) \end{gathered}`

The form of the slope-intercept is

`y=mx+b`

b is the y-intercept (value y at x = 0)

Since at x = 0, y = 1

Then the y-intercept is 1

b = 1

The equation is

`y=(3)/(2)x+1`

The slope is 3/2