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A line passes through the point (-8, 2) and has a slope of34Write an equation in point-slope form for this line.

User Afshin
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To write the equation of a line in point-slope form you use the given point and the slope:

m=3/4

point (- 8 ,2)

You have the next general form of point-slope equation:


y-y_1=m(x-x_1)

The point gives the x1 and y1:

x1= -8

y1= 2

Then, the equation is:


\begin{gathered} y-2=(3)/(4)(x-(-8)) \\ \\ \\ y-2=(3)/(4)(x+8) \end{gathered}

User Javros
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