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T(16, 2) and U(17, 13)What is the mid point?

User Utdiscant
by
8.0k points

1 Answer

3 votes

Answer:

(16.5, 7.5)

Step-by-step explanation:

Given the two endpoints of a line segment AB:


A(x_1,y_1)\text{ and B}(x_2,y_2)

The midpoint of AB is derived using the formula:


((x_1+x_2)/(2),(y_1+y_2)/(2))

Given the points T(16, 2) and U(17, 13), the midpoint of TU therefore, is:


\begin{gathered} ((16+17)/(2),(2+13)/(2)) \\ =((33)/(2),(15)/(2)) \\ =(16.5,7.5) \end{gathered}

The midpoint of TU is (16.5, 7.5).

User Nambi
by
7.7k points

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