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User Samrap
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Question:

Write each of the following equations in y = mx + b form

Solution:

1) Let the equation


2y=\text{ -1x-8}

Dividing both sides of the equation by two, we have that this is equivalent to:


y\text{ = }(-1)/(2)x-(8)/(2)

this is equivalent to:


y\text{ = }(-1)/(2)x-4

Then the above equation is in the form y = mx +b.

2) Consider the following equation:


y-4\text{ = -3(x-3)}

adding to both sides of the equation the number 4, we get:


y\text{ = -3(x-3) + 4}

now, using the distributive property, we get:


y\text{ = -3x+9 + 4}

this is equivalent to:


y\text{ = -3x +13}

Then the above equation is in the form y = mx +b.

3) Let the following equation:


0.2x\text{ + 0.3y = 0.5}

subtracting to both sides of the equation the term 0.2x , we get:


\text{ 0.3y = 0.5}-0.2x

this is equivalent to:


\text{ 0.3y = }-0.2x+0.5

now, dividing both sides of the equation by 0.3, we have that this is equivalent to:


\text{ y = }(-0.2)/(0.3)x+(0.5)/(0.3)

this is equivalent to:


\text{ y = }(-2)/(3)x+(5)/(3)

Then the above equation is in the form y = mx +b.

4) Consider the following equation:


(1)/(4)y+3\text{ = -5x}

subtracting to both sides of the equation the number 3 , we get:


(1)/(4)y\text{ = -5x}-3

now, multiplying both sides of the equation by 4, we get:


y\text{ = -20x-12}

Then the above equation is in the form y = mx +b.

User Daro
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