Question

Use the formula to calculate the stopping distance for a vehicle traveling 45 mph. The tires have a coefficient of friction or 0.8 and the roadway has a grade of 0.15. Round your answer to one decimal place.

Answer 1

`\begin{gathered} d=(v^2_o)/(2g(f+G)) \\ \text{Where:} \\ v_o=45\text{mph} \\ f=0.8 \\ G=0.15 \\ g=(9.8m)/(s^2) \end{gathered}`

Therefore:

`d=(45^2)/(2(9.8)(0.8+0.15))=(2025)/(20.55)=98.54014599\approx98.5`