ANSWER
![-(2√(3))/(3)](https://img.qammunity.org/2023/formulas/advanced-placement-ap/high-school/e5w4dgcvtbxzhbz1pqtek1zacelumm77mt.png)
Step-by-step explanation
We want to find the value of:
![\sec((31\pi)/(6))](https://img.qammunity.org/2023/formulas/mathematics/college/em1p15pobemkav9tz6z7fg73myxzzz43vi.png)
First, we can rewrite the angle by reducing it by 4π i.e. two full rotations of 2π to make the angle between 0 and 2π. The angle then becomes:
![\sec((7\pi)/(6))](https://img.qammunity.org/2023/formulas/mathematics/college/2brk9hyq9jjj7taexv9qmcsa48sfckrilh.png)
This is the same as:
![(1)/(\cos((7\pi)/(6)))](https://img.qammunity.org/2023/formulas/mathematics/college/g72v8b18q0ejrwfdwa51bx8oxb2hzzz1aw.png)
Now, we can apply the reference angle by finding the equivalent value of the angle in the first quadrant:
![(1)/(\cos((7\pi)/(6)))\Rightarrow(1)/(-\cos((\pi)/(6)))](https://img.qammunity.org/2023/formulas/mathematics/college/cxsqlbxxr9vw3r4bzt95t6niwh3kmpwo5j.png)
The value is negative because the reference angle is in the third quadrant and cosine is negative in the third quadrant.
Now, solving this, we have:
![\begin{gathered} (1)/(-(√(3))/(2))\Rightarrow-(2)/(√(3)) \\ \\ -(2)/(√(3))*(√(3))/(√(3)) \\ \\ -(2√(3))/(3) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/mc26zvffrvk7vzfcst1z1czi81wi0e7hq8.png)
That is the answer.