Given:
• Product of two numbers = 1856
,
• Sum of two numbers = 90
Let's find the difference of these two numbers.
Let x represent the bigger number.
Let y represent the smaller number.
We have the system of equations:
• xy = 1856
,
• x + y = 90
Let's solve the system simultaneously using substitution method.
Rewrite the second equation for x:
![x=90-y](https://img.qammunity.org/2023/formulas/mathematics/college/celhj0fp1shodbs8v5fl7eh2rkva6hyr6q.png)
Substitute (90-y) for x in equation 1:
![(90-y)y=1856](https://img.qammunity.org/2023/formulas/mathematics/college/s0jtdke7qdnlescxg2ebm96uub5lvjep35.png)
Apply distributive property:
![90y-y^2=1856](https://img.qammunity.org/2023/formulas/mathematics/college/jk8rpd3j9y2whze7cili1jehk9oexxkcjw.png)
Equate the equation to zero and factor the left side:
![\begin{gathered} 90y-y^2-1856=0 \\ \\ -y^2+90y-1856=0 \\ \\ -(y^2-90y+1856)=0 \\ \\ -(y-58)(y-32)=0 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/wexp0hgfx4sc27zmatt4otlgcig95m66up.png)
Equate the individual factors to zero and solve for y:
![\begin{gathered} y-58=0 \\ \text{Add 58 to both sides:} \\ y-58-58=0+58 \\ y=58 \\ \\ \\ y-32=0 \\ \text{Add 32 to both sides:} \\ y-32+32=0+32 \\ y=32 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/d9cirj0ml5uuz43a9k1efosrijc0iit9pm.png)
Therefore, we have:
y = 32 and 58
Since y is the smaller number, let y be 32.
x is the greater number.
x = 58.
Therefore, the two numbers are:
58 and 32.
To find the difference of the two numbers, subtract the smaller number from the greater number.
58 - 32 = 26
Therefore, the difference of the two numbers is 26.
ANSWER:
C. 26