Question

For each pair of bonds, indicate the more polar bond, and use an arrow to show the direction of polarity in eacg bond.a. P-Br and P-Clb. B-O and B-Sc. B-F and B-I

Answer 1

a. P-Cl.

b. B-O.

c. B-F.

Step-by-step explanation:

To determine what is the more polar bond, we have to calculate the electronegativity difference which you can find in the periodic table. The electronegativity difference that is bigger, will be the more polar bond. Here, we have the electronegativities that we're going to need:

P : 2.1

Br : 2.8

Cl : 3.0

B : 2.0

O : 3.5

S : 2.5

F : 4.0

I : 2.5

a. The electronegativity difference between P-Br is 2.8 - 2.1 = 0.7 and for P-Cl is 3.0 - 2.1 = 0.9, so the most polar here is P-Cl. The arrow indicates the direction of polarity, which is to the most electronegative element, in this case, Cl because is bigger than P:

b. The electronegativity difference of B-O is 3.5 - 2.0 = 1.5 and for B-S is 2.5 - 2.0 = 0.5, so the mos polar would be B-O and the direction of the arrow goes to oxygen (O):

c. The electronegativity difference of B-F is 4.0 - 2.0 = 2.0 and for B-I is 2.5 - 2.0 = 0.5, so the most polar compound is B-F and the direction of the arrow goes to fluorine because is the most electronegative: