Question

Find vertex of y(x-5)^2+2

Answer 1

We can find the vertex of the function by expanding the function and replacing in the following expression:

`x=-(b)/(2a)`

Now, we expand the function:

`y=(x-5)^2+2\Rightarrow y=x^2-10x+27`

Now, we replace in the expression:

`x=-((-10))/(2(1))=5`

Now, we proceed as follows:

We plug the value we got [That is the x-component of the vertex] in the equation and solve for x, that is:

`y=(5)^2-10(5)+27\Rightarrow y=2`

So, the vertex is found in the point (5, 2).