Question

6r = 726r − 6 = 72 − 6r = 66Is Brooke’s solution correct? If the solution is incorrect, explain why it is incorrect and show the correct steps to solve the equation.

Answer 1

Given the question, the following are the solution steps to answer the question.

STEP 1: Write the given solution

`\begin{gathered} 6r=72 \\ 6r-6=72-6 \\ r=66 \end{gathered}`

STEP 2: Determine whether Brooke's solution is correct

Brooke's solution is incorrect because Brooke subtracted the co-efficient of r which is 6 from both sides. Brooke can not use this method since 6 is multiplied to the unknown value which ir and not added to both sides.

The correct step will be to divide both sides by the coefficient of r as seen below:

`\begin{gathered} 6r=72 \\ Coefficeint\text{ of r is 6} \\ Divide\text{ both sides by 6} \\ (6r)/(6)=(72)/(6) \\ r=12 \end{gathered}`