Question

First rewrite 5/7 and 7/10 so that they have a common

Answer 1

First, find the first multiples of 7 and 10 as shown below

`\begin{gathered} 7\rightarrow7,14,21,28,35,42,49,56,63,70,77,... \\ 10\rightarrow10,20,30,40,50,60,70,80... \end{gathered}`

Therefore, the least common multiple of 7 and 10 is 70. Notice that

`\begin{gathered} (5)/(7)*1=(5)/(7)*(10)/(10)=(50)/(70) \\ and \\ (7)/(10)*1=(7)/(10)*(7)/(7)=(49)/(70) \end{gathered}`

Therefore,

`\begin{gathered} (50)/(70)>(49)/(70) \\ \Rightarrow(5)/(7)>(7)/(10) \end{gathered}`

The answers are 5/7=50/70, 7/10=49/70, and 5/7>7/10