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Find the zeroes and state the multiplicity of multiple zeroesY={x+8}{x-3}^4

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y = ( x +8) (x -3) ^4

y = 0

0 = (x +8)

x = -8

The multiplicity of multiple this zero is 1

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y = (x -3) ^4

0 = (x - 3) ^4

0 =(x - 3)

x = 3

In this case, we have a multiplicity

y = (x -3) ^4 = (x-3) (x-3) (x-3) (x-3)

We have four times the same factor, it is repeated

The multiplicity of multiple zeroes is 4

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Answer

zeroes multiplicity

x=3 4

x=-8 1

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