Given the vectors:
![\langle3,4)\text{ and }\langle-8,6\rangle](https://img.qammunity.org/2023/formulas/mathematics/high-school/jw16g9en9i83rka9f12alnlzlxxhlipipt.png)
You need to remember that two vectors are parallel when they have their slopes (in Component Form) are equal.
Then, knowing that:
![m=(rise)/(run)](https://img.qammunity.org/2023/formulas/mathematics/college/x2n7g0mw0ahcbwc8l74u6j55nytkbn89b3.png)
You need to find the slope of each vector:
- The slope of the first vector is:
![m_1=\frac{v_2_{}}{v_1_{}_{}}=(4)/(3)](https://img.qammunity.org/2023/formulas/mathematics/high-school/4k7ye6joh97t3zjach0xrufwgp9fmnp0tb.png)
- The slope of the second vector is:
![m_2=\frac{u_2_{}}{u_1_{}}=(6)/(-8)=-(3)/(4)](https://img.qammunity.org/2023/formulas/mathematics/high-school/y422k9wzzs4p1zmbw8ke0y1t73hu7n00qi.png)
Since:
![m_1\\e m_2](https://img.qammunity.org/2023/formulas/mathematics/high-school/bfp7b7ptonfo9u0ijj3ixego3r0dhn8o3g.png)
The vectors are not parallel.
To find if they are orthogonal, you need to know that, if:
![u\cdot v=0](https://img.qammunity.org/2023/formulas/mathematics/high-school/9w5i93v4mlpj82v453q7suk2mgypuyb13d.png)
The vectors are orthogonal.
Then, it is important to remember that:
![u\cdot v=u_1v_1+u_2v_2](https://img.qammunity.org/2023/formulas/mathematics/high-school/k6o2ekj1xwdqui0kw97grjuzjlwg8qg8to.png)
You can set up that:
![\begin{gathered} u_1=-8 \\ u_2=6 \\ v_1=3_{} \\ v_2=4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/dhnr2c9a5gyzvmq6xp3bn6ihf8zv9gv62k.png)
Substituting values and evaluating, you get:
![u\cdot v=(-8)(3)+(6)(4)=-24+24=0](https://img.qammunity.org/2023/formulas/mathematics/high-school/kl43b3nutgqeizi5lmo7ie7z5guvo4jpw7.png)
Therefore, they are orthogonal.
Hence, the answer is: Orthogonal.