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If cos x= √2/2 and x is a fourth quadrant angle, evaluate tan x

User Botto
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Given that;


\begin{gathered} \cos x=\frac{\sqrt[]{2}}{2} \\ and\text{ x is a fourth angle quadrant.} \end{gathered}

Note that cosine is positive on the fourth angle quadrant while tangent is negative.

From;


\begin{gathered} \cos x=\frac{\sqrt[]{2}}{2} \\ \text{adjacent}=\sqrt[]{2},\text{ hypotenuse= 2} \\ \text{opposite}=\text{ }\sqrt[]{2^2-(\sqrt[]{2})^2} \\ \text{opposite}=\sqrt[]{4-2} \\ \text{opposite}=\sqrt[]{2} \\ \end{gathered}

Thus, the tangent is;


\begin{gathered} \tan x=\frac{-\sqrt[]{2}}{\sqrt[]{2}} \\ \tan x=-1 \end{gathered}

If cos x= √2/2 and x is a fourth quadrant angle, evaluate tan x-example-1
User Johnny Alpha
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