Question

work done by a force is given by the expression W= Fd cos theta , where F is the magnitude of the force, d is the distance traveled, and 8 is the angle of theapplied force to the direction of motion. Calculate the amount of work done by a 5 N force acting at a 75°-degree angle to move a box 30m

Answer 1

We are given that:

`\begin{gathered} \theta=75^(\circ), \\ d=30m, \\ F=5N. \end{gathered}`

Substituting the given values in the formula for the work done, we get ( we will omit the units):

`W=5*30*cos(75^(\circ)).`

Computing the above multiplications, we get:

`W=150((√(6)-√(2))/(4)).`

Answer:

`150((√(6)-√(2))/(4)).`