The formula for compound interest is:
![A=P(1+(r)/(n))^(nt)](https://img.qammunity.org/2023/formulas/mathematics/high-school/39foo2gerf9tf1ffk32zwshrn339mz02kv.png)
Where A is the current amount, P is the initial amount, r is the interest rate, n is the number of times the interest is applied in a period, and t is the period. Then, in our problem,
![A=17763,P=9300,n=1,r=0.13](https://img.qammunity.org/2023/formulas/mathematics/college/z5wm7rm347beim47rewfryylm2r9jraqm2.png)
We need to solve for t, as follows:
![\begin{gathered} A=P(1+r)^t,n=1 \\ \Rightarrow(1+r)^t=(A)/(P) \\ \Rightarrow\ln ((1+r)^t)=\ln ((A)/(P)) \\ \Rightarrow t\ln (1+r)=\ln ((A)/(P)) \\ \Rightarrow t=(\ln((A)/(P)))/(\ln(1+r)) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/tl2v6kg8q64tzu4p3kohqtbuol5l76a8y2.png)
Therefore (using numeric values),
![t=(\ln ((17763)/(9300)))/(\ln (1.13))\approx5.3](https://img.qammunity.org/2023/formulas/mathematics/college/guaaf59b30myxbc31pt9o1thrz9j7ayct4.png)
Therefore, we will reach that total amount after 5.3 years of compound interest.