Question

See photo. I am particularly confused about how specific latent heat factors into it

Answer 1

Given:

Initial temperature, T1 = 20.0 degrees Celsius

Final temperature, T2 = -1.5 degrees celsius

Energy, Q= 165 kJ

Specific heat capacity of the mixture, c = 3500 J/kg degrees Celsius

Sppecific latent heat, L = 255000 J/kg

Let's find the mass of the mixture.

Apply the formula:

`Q=mc\Delta T+mL`

Where:

m is the mass

Rewrite the formula for m

Thus, we have:

`m=(Q)/(c\Delta T+L)`

Now, input values and solve for m:

`\begin{gathered} m=(Q)/(c(T_2-T_1)+L) \\ \\ m=(165000)/(3500(-1.5-20)+255000) \\ \\ m=(165000)/(3500(-21.5)+255000) \end{gathered}`

Solving further:

`\begin{gathered} m=(165000)/(-75250+255000) \\ \\ m=(165000)/(179750) \\ \\ m=0.92kg \end{gathered}`

Therefore, the mass of the mixture is 0.92 kg