Question

What is an equation of the line that passes through the points (1,1) and (7, -5)?Put your answer in fully reduced form.

Answer 1

We need to find the slope

`\text{slope (m)=}(y_2-y_1)/(x_2-x_1)`

`x_1=1_{}_{}`
`y_(1=)1_{}`
`x_2=7`
`y_2=-5`

substitute the values in the formula given above

`\text{slope (m) =}(-5-1)/(7-1)`
`=(-6)/(6)=-1`

Find the intercept using y = mx + b

where b is the intercept

x = 1 y= 1 and m = -1

Now solve for b

1 = 1(-1) + b

1 = -1 + b

1 + 1 = b

2 = b

Form the equation by substituting the value of m and b in y = mx + b

That is;

y = - x + 2