Question

A 40.0 kilogram mass is moving across a horizontal surface at 5.0m/s. What is the magnitude of the net force required to bring the mass to a stop in 8.0 seconds?

Answer 1

Answer:

The magnitude of the net force required to bring the mass to a stop is 25 N

Step-by-step explanation:

The mass, m = 40.0 kg

The initial velocity, u = 5.0 m/s

Since the mass comes to a stop in 8.0 seconds

The final velocity, v = 0 m/s

The time, t = 8.0 seconds

The magnitude of the netforce is given by the formula:

`\begin{gathered} F=|(m(v-u))/(t)| \\ F=|(40(0-5))/(8)| \\ F=|(40(-5))/(8)| \\ F=|-(200)/(8)| \\ F=|-25| \\ F=25N \end{gathered}`

The magnitude of the net force required to bring the mass to a stop is

25 N