25.0k views
0 votes
A resort in Orlando, Florida offers vacationers two boat ride plans. Plan A gives 3 nights lodging and 5 boat rides for a total cost of $625. Plan B gives 5 nights lodging and 6 boat rides for a total of $960What is the cost of each boat ride?

User Nolawi
by
5.4k points

1 Answer

4 votes

Given is Plan A gives 3 nights lodging and 5 boat rides for a total cost of $625.

and Plan B gives 5 nights lodging and 6 boat rides for a total of $960.

Let x be the cost of night lodging and y be the cost of the boat ride.

The given can be written as follows.


3x+5y=625
5x+6y=960

Multiply equation 3x+5y=625 by 5 as follows.


5*3x+5*5y=5*625


15x+25y=3125\text{ take it as equation (1).}

Multiply equation 5x+6y=960 by 3 as follows.


3*5x+3*6y=3*960


15x+18y=2880\text{ take this as equation (2).}

Substract equation (2) from equation (1) to compute the value of y.


(15x+25y)-(15x+18y)=3125-2880


15x+25y-15x-18y=3125-2880

Solve like terms.


7y=245

Dividing by 7 into both sides, we get


(7y)/(7)=(245)/(7)


y=35

Hence we get the cost of the boat ride is $35.

Substitute y=35 in 3x+5y=625 to compute the value of y.


3x+5(35)=625


3x+175=625

Adding -175 on both sides, we get


3x+175-175=625-175

Solve like terms.


3x=450

Dividing by 3 into both sides, we get


(3x)/(3)=(450)/(3)


x=150

Hence the cost of night lodging is $150.

Result :

The cost of night lodging is $150.

The cost of the boat ride is $35.

The cost of each boat is $150 and $35.

User Gur Galler
by
6.2k points