72.0k views
4 votes
In ΔABC, Z is the midpoint of AC and Y is the midpoint of BC. If YZ = 21 and AB = (2x – 4), what is the value of x?

In ΔABC, Z is the midpoint of AC and Y is the midpoint of BC. If YZ = 21 and AB = (2x-example-1
User Wschopohl
by
8.5k points

1 Answer

2 votes

ANSWER

C. 23

Step-by-step explanation

We are given that Z is the midpoint of AC and Y is the midpoint of BC.

According to the midpoint theorem of triangles, the midsegment of a triangle (YZ) is equal to half the length of side parallel to it (AB)

This means that:


YZ\text{ = }(1)/(2)AB

So, we have that:


\begin{gathered} 21\text{ = }(1)/(2)(2x\text{ - 4)} \\ 21\text{ = x - 2} \\ \text{Collect like terms:} \\ \Rightarrow\text{ x = 21 + 2} \\ \text{x = 23} \end{gathered}

The answer is Option C.

User SKeurentjes
by
8.3k points

Related questions

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories