Given the line segment BE
As shown:
BC = 3x + 47
CD = y
BD = x + 27
CE = x + 26
DE = 10
To find the length of BE, we will find the values of x and y
So,

Solve the equations (1) and (2) for x

Substitute at (2) to find y

The length of BE = BC + CD + DE

Substitute with x and y:

So, the answer will be ⇒ BE = 25