We are given two set of systems of equation
y = -4x - 7 --------- equation 1
3x - 2y = 14 ------- equation 2
Firstly, substitute equation 1 into equation 2
3x - 2(-4x - 7) = 14
Open the parenthesis
3x - 8x + 14 = 14
Collect the like terms
3x - 8x = 14 - 14
-5x = 0
Divide both sides by -5
x = 0/-5
x = 0
To find y, substitute the value of x in equation 1
y = -4x - 7
y = -4(0) - 7
y = 0 - 7
y = -7
The answer is (0, -7)