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10. A 9500 g block of granite has an original temperature of 15.0°C. What will be the final temperature of this granite if 5.5 x 10^9 J of heat energy are added to the granite?

User Evengard
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1 Answer

1 vote

Step-by-step explanation:

We have to find the final temperature of a block of granite. We have to apply this formula:

Q = m * C * ΔT

Where Q is the amount of heat gained or released, m is the mass, C is the specific heta and ΔT is the temperature change.

Q = 5.5 *10^9 J (positive because the block gained the energy)

m = 9500 g

C = 0.77 J/(g*°C)

ΔT = Tfinal - Tinitial

ΔT = Tfinal - 15.0 °C

We can replace these values in the formula and solve it for the final temperature to get the answer to our problem.

Q = m * C * ΔT

5.5 * 10^9 J = 9500 g * 0.77 J/(g*°C) * (Tfinal - 15.0 °C)

5.5 * 10^9 J/(9500 g * 0.77 J/(g*°C) = Tfinal - 15.0 °C

751880 °C = Tfinal - 15.0 °C

Tfinal = 751880 °C + 15.0 °C

Tfinal = 751895 °C = 752000 °C

Answer: the final temperature of the granite is 752000 °C.

User Steve Jones
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