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How many different distinguishable orders can the letters of the word precalculus be arranged

User Bhupesh
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1 Answer

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This is a problem of permutation or arrangements, the word PRECALCULUS has 11 letters, of which 3 letters appear twice, we want to get the number of indistinguishable arrangements, this is how we do it,


P_r^n=(n!)/((n-r)!)

For our problem, what we do is


=\text{ }\frac{11!}{2!\text{ 2! 2!}}\text{ = }(11!)/(8)\text{ = 4989600 orders}

User SSBakh
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