Question

Solve the equation by using quadratic formula . Show your work! Answer maybe in radical or decimal form .

2x^2 + 4x – 5 = 0

Answer 1

`x_1=(-2+√(14))/(2)\approx 0.871,x_2=(-2-√(14))/(2)\approx-2.871`

Explanation:

`2x^2+4x-5=0`

`x=(-b\pm√(b^2-4ac))/(2a)`

`x=(-4\pm√(4^2-4(2)(-5)))/(2(2))`

`x=(-4\pm√(16+40))/(4)`

`x=(-4\pm√(56))/(4)`

`x=(-4\pm2√(14))/(4)`

`x=(-2\pm√(14))/(2)`

`x_1=(-2+√(14))/(2)\approx 0.871,x_2=(-2-√(14))/(2)\approx-2.871`