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19 votes
19 votes
a train is leaving the station and goes from 3m/s to 30 m/s in 12 s. The acceleration of the train is

User Trevor D
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1 Answer

20 votes
20 votes

Answer:2.25 m/s^2

Explanation:

a = (v-u)/t = 27/12 = 2.25 m/s^2

User Imke Krueger
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