Question

An airplane has just enough fuel for a 6 hour flight. How far can it fly, roundtrip, in which during the first leg of the trip, it flies with the wind at 235 miles per hour, and during the return trip, it flies against the wind at 190 miles per hour? Round to the nearest thousandth.

Answer 1

First leg of the trip:

let the time used during the first leg of the trip be x

Speed = 235miles/hr

Since distance = speed * time

distnace = 235x

On the return trip:

Speed = 190miles/hr

The time spent will be 6-x

Distance covered = 190(6-x)

Since the distance covered on both trips are the same hence;

235x = 190(6-x)

Open the paremthesis

235x = 1140-190x

235x + 190x = 1140

425x = 1140

x = 1140/425

x = 2.6824

Calculate the distance;

first leg

distance = 235x

distance = 235(2.6824)

distance = 630.353miles

Returm trip will also be 630.353

Total distance for both trip = 630.353+630.353 = 1260.706miles (to the neareest thousandth)