Question

2 H2O2 → 02 + 2 H2OI decompose a container of 156 g of H2O2, and find that 23 L of O2, was produced. Find the percent yield

Answer 1

44.77%

Step-by-step explanation

Given:

Mass of H₂O₂ decomposed = 156 g

Actual yield of O₂ = 23 L

Equation: 2H₂O₂ → O₂ + 2H₂O

What to find:

The percent yield of O₂.

Step-by-step solution:

To get the percent yield of O₂, you need to first calculate the theoretical yield of O₂.

From the given equation, 2 mol of H₂O₂ produced 1 mol of O₂

Note: 1 mol H₂O₂ = 34.0147 g H₂O₂, so 2 mol H₂O₂ = 2 x 34.0147 g = 68.0294 g

Also, 1 mol O₂ = 22.4 L

So we can say, 68.0294 g H₂O₂ produced 22.4 L O₂

Therefore, 156 g H₂O₂ will produce:

Hence, the theoretical yield of O₂ = 51.37 L

Now, the percent yield of O₂ can be calculated using the formula below:

`Percent\text{ yield }=\frac{Actual\text{ yield}}{Theorectical\text{ yield}}*100`

Actual yield of O₂ = 23 L

Theoretical yield O₂ = 51.37 L

So the percent yield of O₂ is:

Hence, the percent yield of O₂ is 44.77%