Question

V^(1/2)+1=0Solve equation

Answer 1

From the problem, we have :

`v^{(1)/(2)}+1=0`

Subtract 1 to both sides of the equation :

`\begin{gathered} v^{(1)/(2)}+1-1=-1 \\ v^{(1)/(2)}=-1 \end{gathered}`

Square both sides :

`(v^{(1)/(2)})^2=(-1)^2`

Note that the imaginary number i = √-1

and i^2 = (√-1)^2 = -1

We can replace the right side of the equation as :

`\begin{gathered} (v^{(1)/(2)})^2=(-1)^2 \\ v=i^2 \end{gathered}`

The answer is i^2