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Hw #5 trapezoids and kites practice

Please help me answer any of these few questions, any help is greatly appreciated!!!

Hw #5 trapezoids and kites practice Please help me answer any of these few questions-example-1
Hw #5 trapezoids and kites practice Please help me answer any of these few questions-example-1
Hw #5 trapezoids and kites practice Please help me answer any of these few questions-example-2
Hw #5 trapezoids and kites practice Please help me answer any of these few questions-example-3

1 Answer

6 votes

Answer:

Explanation:

First Problem:

Given: m< ABC = 70; m< ADC = 46

line AC and line BD are perpendicular bisectors based on the definition of parallelograms.

m< 4 = 90

Line BD bisects < ABC

70/2 = 35

m< 2 = 35 ; m< 3 = 35

Line BD bisects < ADC

46/2 = 23

m< 8 = 23 ; m< 9 = 23

All the three angles of a triangle add up to 180.

180 - (90 + 35) = 55

m< 1 = 55 ; m< 5 = 55

180 - (90 + 23) = 67

m< 6 = 67 ; m< 7 = 67

Third Problem:

<BCE = <ECD because line AC bisects <BCD

9x - 1 = 2x + 13

9x - 2x = 13 + 1

7x - 14

x = 2 ; m< ECD = 2

line AC and line BD are perpendicular bisectors based on the definition of parallelograms. So, <CED = 90

All the three angles of a triangle add up to 180.

180 - (90 + 2) = 88

m< EDC = 88

User Mohit M
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