Question

2x^2-8x-5=0Completing the square gives us: (x- Answer )^2 = AnswerEnter your solutions below from smallest to largest. If a solution is repeated type that answer for both values of x. If your answer is not an integer then type it as a decimal rounded to the nearest hundredth.x=Answer and x=Answer

Answer 1

The given equation is:

`2x^2-8x-5=0`

square is:

`\begin{gathered} 2x^2-8x-5=0 \\ 2x^2-8x=5 \\ x^2-4x=(5)/(2) \\ x^2-4x+4=(5)/(2)+4 \\ (x-2)^2=(13)/(2) \\ \end{gathered}`

Then the value of x:

`\begin{gathered} (x-2)^2=(13)/(2) \\ x-2=\pm\sqrt[]{(13)/(2)} \\ x=2\pm\sqrt[]{(13)/(2)} \\ x=2+\sqrt[]{(13)/(2)};x=2-\sqrt[]{(13)/(2)} \end{gathered}`