ANSWER

Step-by-step explanation
b) We want to find the change in gravitational potential energy of the lorry.
The change in gravitational potential energy is given by:

where m = mass of the lorry
g = acceleration due to gravity
Δh = change in height
Let us make a sketch of the problem:
To find the change in height, we have to apply the trigonometric ratios:

Therefore, the change in height is:

Therefore, the change in gravitational potential energy of the lorry is:

That is the answer.