Question

Am I correct And if not please help Quadratic formula

Answer 1

We have the equation:

`2x^2-2x+3`

Where:

a = 2

b = -2

c = 3

Using the formula:

`x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}`

This is:

`x=\frac{-(-2)\pm\sqrt[]{(-2)^2-4(2)(3)}}{2(2)}`
`\begin{gathered} x=\frac{2\pm\sqrt[]{4-24}}{4} \\ x=\frac{2\pm\sqrt[]{-20}}{4}\text{ } \end{gathered}`

Answer:

`\begin{gathered} x1=\frac{2+\sqrt[]{-20}}{4} \\ \text{and} \\ x2=\frac{2-\sqrt[]{-20}}{4} \end{gathered}`