To find a perpendicular line using the equation of the original line, we just need to transform the slope.
The equation of the original line is:
![y=(x)/(4)-4](https://img.qammunity.org/2023/formulas/mathematics/college/8pbtlbq3kg9ccjhtvom5uvoqxxz2f9by5u.png)
So, the slope is 1/4. To get the slope of a perpendicular line, we invert it and change its sign, so the new slope is:
![s=-(1)/((1)/(4))=-4](https://img.qammunity.org/2023/formulas/mathematics/college/kvgiefqp1o1qxfj2li7aht4tz9rz0anoxw.png)
With the slope and a point, (-8,5), we can use the slope-intercept form for a line, which is:
![(y-y_0)=s(x-x_0)](https://img.qammunity.org/2023/formulas/mathematics/college/ooy2butby3rvawny2wdb7ap3zc9g5slbz1.png)
Where y0 and x0 are the coordinates of the point. So:
![\begin{gathered} y-5=-4(x-(-8)) \\ y=-4(x+8)+5 \\ y=-4x-32+5 \\ y=-4x-27 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/loio5mnnt13nc7k4qnmrn1qgxtl1zpek8y.png)