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Factor the following trinomial completely 2x^3+8x^2-10x

1 Answer

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possible factors that can be zeroes of the trinomial are


\pm2,\text{ }\pm5,\text{ }\pm10
\begin{gathered} \text{coefficient from the equation are} \\ 2\text{ +8 -10},\text{ Using -5 to check} \\ -5|\text{ 2 +8 }-10 \\ \text{ -10 +10 } \\ ---------- \\ \text{ 2x}^2-2x\text{ +0} \\ \\ \end{gathered}

Factorizing 2x^2 -2x we have 2x(x-1)

so the factors are (x+5)(2x)(x-1)

User Ashouri
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